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1331412120230 = 25671987182269
BaseRepresentation
bin10011010111111110010…
…110001011001010100110
311201021121101210111101112
4103113332112023022212
5133303213000321410
62455350422225022
7165122430203003
oct23277626131246
94637541714345
101331412120230
11473715483035
12196053285172
1398722bc292a
144862537c8aa
15249769da105
hex135fe58b2a6

1331412120230 has 16 divisors (see below), whose sum is σ = 2432311098480. Its totient is φ = 524616118752.

The previous prime is 1331412120167. The next prime is 1331412120331. The reversal of 1331412120230 is 320212141331.

It is a junction number, because it is equal to n+sod(n) for n = 1331412120196 and 1331412120205.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 993590465 + ... + 993591804.

It is an arithmetic number, because the mean of its divisors is an integer number (152019443655).

Almost surely, 21331412120230 is an apocalyptic number.

1331412120230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1331412120230 is a deficient number, since it is larger than the sum of its proper divisors (1100898978250).

1331412120230 is a wasteful number, since it uses less digits than its factorization.

1331412120230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1987182343.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1331412120230 its reverse (320212141331), we get a palindrome (1651624261561).

The spelling of 1331412120230 in words is "one trillion, three hundred thirty-one billion, four hundred twelve million, one hundred twenty thousand, two hundred thirty".

Divisors: 1 2 5 10 67 134 335 670 1987182269 3974364538 9935911345 19871822690 133141212023 266282424046 665706060115 1331412120230