Base | Representation |
---|---|
bin | 10011010111111110010… |
… | …111010000101100111101 |
3 | 11201021121102022222002112 |
4 | 103113332113100230331 |
5 | 133303213033430203 |
6 | 2455350432303405 |
7 | 165122432500253 |
oct | 23277627205475 |
9 | 4637542288075 |
10 | 1331412405053 |
11 | 473715658025 |
12 | 1960533a1b65 |
13 | 98722c92473 |
14 | 486254145d3 |
15 | 24976a446d8 |
hex | 135fe5d0b3d |
1331412405053 has 2 divisors, whose sum is σ = 1331412405054. Its totient is φ = 1331412405052.
The previous prime is 1331412405031. The next prime is 1331412405077. The reversal of 1331412405053 is 3505042141331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 796017271204 + 535395133849 = 892198^2 + 731707^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331412405053 - 26 = 1331412404989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331412405353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665706202526 + 665706202527.
It is an arithmetic number, because the mean of its divisors is an integer number (665706202527).
Almost surely, 21331412405053 is an apocalyptic number.
It is an amenable number.
1331412405053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331412405053 is an equidigital number, since it uses as much as digits as its factorization.
1331412405053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 1331412405053 its reverse (3505042141331), we get a palindrome (4836454546384).
The spelling of 1331412405053 in words is "one trillion, three hundred thirty-one billion, four hundred twelve million, four hundred five thousand, fifty-three".
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