Base | Representation |
---|---|
bin | 10011010111111110010… |
… | …111010000101100100111 |
3 | 11201021121102022222001201 |
4 | 103113332113100230213 |
5 | 133303213033430111 |
6 | 2455350432303331 |
7 | 165122432500222 |
oct | 23277627205447 |
9 | 4637542288051 |
10 | 1331412405031 |
11 | 473715658005 |
12 | 1960533a1b47 |
13 | 98722c92457 |
14 | 486254145b9 |
15 | 24976a446c1 |
hex | 135fe5d0b27 |
1331412405031 has 2 divisors, whose sum is σ = 1331412405032. Its totient is φ = 1331412405030.
The previous prime is 1331412405007. The next prime is 1331412405053. The reversal of 1331412405031 is 1305042141331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1331412405031 - 227 = 1331278187303 is a prime.
It is a super-2 number, since 2×13314124050312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331413405031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665706202515 + 665706202516.
It is an arithmetic number, because the mean of its divisors is an integer number (665706202516).
Almost surely, 21331412405031 is an apocalyptic number.
1331412405031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331412405031 is an equidigital number, since it uses as much as digits as its factorization.
1331412405031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 1331412405031 its reverse (1305042141331), we get a palindrome (2636454546362).
The spelling of 1331412405031 in words is "one trillion, three hundred thirty-one billion, four hundred twelve million, four hundred five thousand, thirty-one".
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