Base | Representation |
---|---|
bin | 10011010111111110011… |
… | …011000100110101100111 |
3 | 11201021121111012202210202 |
4 | 103113332123010311213 |
5 | 133303213312430111 |
6 | 2455350505541115 |
7 | 165122444133533 |
oct | 23277633046547 |
9 | 4637544182722 |
10 | 1331413405031 |
11 | 473716180356 |
12 | 1960537a479b |
13 | 98723252678 |
14 | 486255d4bc3 |
15 | 24976b90b3b |
hex | 135fe6c4d67 |
1331413405031 has 2 divisors, whose sum is σ = 1331413405032. Its totient is φ = 1331413405030.
The previous prime is 1331413404991. The next prime is 1331413405067. The reversal of 1331413405031 is 1305043141331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1331413405031 - 26 = 1331413404967 is a prime.
It is a super-2 number, since 2×13314134050312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1331413404985 and 1331413405003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331413005031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665706702515 + 665706702516.
It is an arithmetic number, because the mean of its divisors is an integer number (665706702516).
Almost surely, 21331413405031 is an apocalyptic number.
1331413405031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331413405031 is an equidigital number, since it uses as much as digits as its factorization.
1331413405031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 1331413405031 its reverse (1305043141331), we get a palindrome (2636456546362).
The spelling of 1331413405031 in words is "one trillion, three hundred thirty-one billion, four hundred thirteen million, four hundred five thousand, thirty-one".
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