Base | Representation |
---|---|
bin | 10011010111111110011… |
… | …110010100101101001101 |
3 | 11201021121112211000202012 |
4 | 103113332132110231031 |
5 | 133303214022201321 |
6 | 2455350540111005 |
7 | 165122454311042 |
oct | 23277636245515 |
9 | 4637545730665 |
10 | 1331414256461 |
11 | 473716702013 |
12 | 196053b35465 |
13 | 98723490083 |
14 | 486257771c9 |
15 | 24976cad05b |
hex | 135fe794b4d |
1331414256461 has 2 divisors, whose sum is σ = 1331414256462. Its totient is φ = 1331414256460.
The previous prime is 1331414256421. The next prime is 1331414256463. The reversal of 1331414256461 is 1646524141331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 981298266025 + 350115990436 = 990605^2 + 591706^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331414256461 - 214 = 1331414240077 is a prime.
Together with 1331414256463, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331414256463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665707128230 + 665707128231.
It is an arithmetic number, because the mean of its divisors is an integer number (665707128231).
Almost surely, 21331414256461 is an apocalyptic number.
It is an amenable number.
1331414256461 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331414256461 is an equidigital number, since it uses as much as digits as its factorization.
1331414256461 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 207360, while the sum is 41.
Adding to 1331414256461 its reverse (1646524141331), we get a palindrome (2977938397792).
The spelling of 1331414256461 in words is "one trillion, three hundred thirty-one billion, four hundred fourteen million, two hundred fifty-six thousand, four hundred sixty-one".
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