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1331414256461 is a prime number
BaseRepresentation
bin10011010111111110011…
…110010100101101001101
311201021121112211000202012
4103113332132110231031
5133303214022201321
62455350540111005
7165122454311042
oct23277636245515
94637545730665
101331414256461
11473716702013
12196053b35465
1398723490083
14486257771c9
1524976cad05b
hex135fe794b4d

1331414256461 has 2 divisors, whose sum is σ = 1331414256462. Its totient is φ = 1331414256460.

The previous prime is 1331414256421. The next prime is 1331414256463. The reversal of 1331414256461 is 1646524141331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 981298266025 + 350115990436 = 990605^2 + 591706^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331414256461 - 214 = 1331414240077 is a prime.

Together with 1331414256463, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1331414256463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665707128230 + 665707128231.

It is an arithmetic number, because the mean of its divisors is an integer number (665707128231).

Almost surely, 21331414256461 is an apocalyptic number.

It is an amenable number.

1331414256461 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331414256461 is an equidigital number, since it uses as much as digits as its factorization.

1331414256461 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 207360, while the sum is 41.

Adding to 1331414256461 its reverse (1646524141331), we get a palindrome (2977938397792).

The spelling of 1331414256461 in words is "one trillion, three hundred thirty-one billion, four hundred fourteen million, two hundred fifty-six thousand, four hundred sixty-one".