Base | Representation |
---|---|
bin | 11000110011001101… |
… | …10111010001110111 |
3 | 1021100220121201001011 |
4 | 30121212313101313 |
5 | 204232004121213 |
6 | 10041104213051 |
7 | 650642361046 |
oct | 143146672167 |
9 | 37326551034 |
10 | 13314520183 |
11 | 5712777098 |
12 | 26b700a187 |
13 | 13425b4913 |
14 | 90443c55d |
15 | 52dd7d03d |
hex | 3199b7477 |
13314520183 has 2 divisors, whose sum is σ = 13314520184. Its totient is φ = 13314520182.
The previous prime is 13314520001. The next prime is 13314520187. The reversal of 13314520183 is 38102541331.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (38102541331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13314520183 - 225 = 13280965751 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13314520187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6657260091 + 6657260092.
It is an arithmetic number, because the mean of its divisors is an integer number (6657260092).
Almost surely, 213314520183 is an apocalyptic number.
13314520183 is a deficient number, since it is larger than the sum of its proper divisors (1).
13314520183 is an equidigital number, since it uses as much as digits as its factorization.
13314520183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
The spelling of 13314520183 in words is "thirteen billion, three hundred fourteen million, five hundred twenty thousand, one hundred eighty-three".
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