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133146016544 = 254160813017
BaseRepresentation
bin111110000000000011…
…1101111101100100000
3110201200011201110000002
41330000013233230200
54140140340012134
6141055541115132
712422324316152
oct1740007575440
9421604643002
10133146016544
1151515500a02
122197a3b8aa8
13c72b8c1a98
146631240ad2
1536e414b87e
hex1f001efb20

133146016544 has 12 divisors (see below), whose sum is σ = 262131220134. Its totient is φ = 66573008256.

The previous prime is 133146016517. The next prime is 133146016561. The reversal of 133146016544 is 445610641331.

It can be written as a sum of positive squares in only one way, i.e., 130566595600 + 2579420944 = 361340^2 + 50788^2 .

It is a junction number, because it is equal to n+sod(n) for n = 133146016498 and 133146016507.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2080406477 + ... + 2080406540.

Almost surely, 2133146016544 is an apocalyptic number.

It is an amenable number.

133146016544 is a deficient number, since it is larger than the sum of its proper divisors (128985203590).

133146016544 is an equidigital number, since it uses as much as digits as its factorization.

133146016544 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4160813027 (or 4160813019 counting only the distinct ones).

The product of its (nonzero) digits is 103680, while the sum is 38.

Adding to 133146016544 its reverse (445610641331), we get a palindrome (578756657875).

The spelling of 133146016544 in words is "one hundred thirty-three billion, one hundred forty-six million, sixteen thousand, five hundred forty-four".

Divisors: 1 2 4 8 16 32 4160813017 8321626034 16643252068 33286504136 66573008272 133146016544