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13317944047937 is a prime number
BaseRepresentation
bin1100000111001101001101…
…0100101111100101000001
31202011011221102022122020122
43001303103110233211001
53221200122134013222
644154102400550025
72543122032411434
oct301632324574501
952134842278218
1013317944047937
114275121242881
1215b1134622315
13757b52256c69
1434084038b81b
1518166c34aa42
hexc1cd352f941

13317944047937 has 2 divisors, whose sum is σ = 13317944047938. Its totient is φ = 13317944047936.

The previous prime is 13317944047841. The next prime is 13317944047939. The reversal of 13317944047937 is 73974044971331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10062954350656 + 3254989697281 = 3172216^2 + 1804159^2 .

It is a cyclic number.

It is not a de Polignac number, because 13317944047937 - 218 = 13317943785793 is a prime.

Together with 13317944047939, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13317944047937.

It is not a weakly prime, because it can be changed into another prime (13317944047939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6658972023968 + 6658972023969.

It is an arithmetic number, because the mean of its divisors is an integer number (6658972023969).

Almost surely, 213317944047937 is an apocalyptic number.

It is an amenable number.

13317944047937 is a deficient number, since it is larger than the sum of its proper divisors (1).

13317944047937 is an equidigital number, since it uses as much as digits as its factorization.

13317944047937 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48009024, while the sum is 62.

The spelling of 13317944047937 in words is "thirteen trillion, three hundred seventeen billion, nine hundred forty-four million, forty-seven thousand, nine hundred thirty-seven".