Base | Representation |
---|---|
bin | 1100000111010100110111… |
… | …1000000010010010101111 |
3 | 1202011101020201011220212011 |
4 | 3001311031320002102233 |
5 | 3221213330012314413 |
6 | 44155042405422051 |
7 | 2543224006630534 |
oct | 301651570022257 |
9 | 52141221156764 |
10 | 13320000119983 |
11 | 4275a868a8177 |
12 | 15b160910a927 |
13 | 7580bc20443b |
14 | 340997480d8b |
15 | 18173cad733d |
hex | c1d4de024af |
13320000119983 has 2 divisors, whose sum is σ = 13320000119984. Its totient is φ = 13320000119982.
The previous prime is 13320000119981. The next prime is 13320000120013. The reversal of 13320000119983 is 38991100002331.
It is a weak prime.
It is an emirp because it is prime and its reverse (38991100002331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13320000119983 - 21 = 13320000119981 is a prime.
Together with 13320000119981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13320000119981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660000059991 + 6660000059992.
It is an arithmetic number, because the mean of its divisors is an integer number (6660000059992).
Almost surely, 213320000119983 is an apocalyptic number.
13320000119983 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320000119983 is an equidigital number, since it uses as much as digits as its factorization.
13320000119983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34992, while the sum is 40.
The spelling of 13320000119983 in words is "thirteen trillion, three hundred twenty billion, one hundred nineteen thousand, nine hundred eighty-three".
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