1332001315 has 4 divisors (see below), whose sum is σ = 1598401584. Its totient is φ = 1065601048.

The previous prime is 1332001301. The next prime is 1332001331. The reversal of 1332001315 is 5131002331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1332001315 - 2⁵ = 1332001283 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1332001292 and 1332001301.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133200127 + ... + 133200136.

It is an arithmetic number, because the mean of its divisors is an integer number (399600396).

Almost surely, 2^1332001315 is an apocalyptic number.

1332001315 is a deficient number, since it is larger than the sum of its proper divisors (266400269).

1332001315 is an equidigital number, since it uses as much as digits as its factorization.

1332001315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 266400268.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 1332001315 is about 36496.5931971739. The cubic root of 1332001315 is about 1100.2757752087.

Adding to 1332001315 its reverse (5131002331), we get a palindrome (6463003646).

The spelling of 1332001315 in words is "one billion, three hundred thirty-two million, one thousand, three hundred fifteen".