Base | Representation |
---|---|
bin | 10011011000100001100… |
… | …100101010001110011111 |
3 | 11201100010120212101201001 |
4 | 103120201210222032133 |
5 | 133310420244320111 |
6 | 2455525213331131 |
7 | 165143164465333 |
oct | 23304144521637 |
9 | 4640116771631 |
10 | 1332003120031 |
11 | 473999043a21 |
12 | 196199196aa7 |
13 | 987b8489a5c |
14 | 4867da617c3 |
15 | 249ad82b1c1 |
hex | 1362192a39f |
1332003120031 has 2 divisors, whose sum is σ = 1332003120032. Its totient is φ = 1332003120030.
The previous prime is 1332003119989. The next prime is 1332003120043. The reversal of 1332003120031 is 1300213002331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1332003120031 - 215 = 1332003087263 is a prime.
It is a super-2 number, since 2×13320031200312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1332003119990 and 1332003120008.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1332003129031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666001560015 + 666001560016.
It is an arithmetic number, because the mean of its divisors is an integer number (666001560016).
Almost surely, 21332003120031 is an apocalyptic number.
1332003120031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332003120031 is an equidigital number, since it uses as much as digits as its factorization.
1332003120031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 1332003120031 its reverse (1300213002331), we get a palindrome (2632216122362).
The spelling of 1332003120031 in words is "one trillion, three hundred thirty-two billion, three million, one hundred twenty thousand, thirty-one".
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