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13320221213040 = 24357107241349881
BaseRepresentation
bin1100000111010101101100…
…0011011100000101110000
31202011101211010012121111220
43001311123003130011300
53221214303112304130
644155120344305040
72543232333115650
oct301653303340560
952141733177456
1013320221213040
11427608a687705
1215b166b172180
13758125c65531
143409b8994360
1518175220b410
hexc1d5b0dc170

13320221213040 has 640 divisors, whose sum is σ = 48021826406400. Its totient is φ = 2991646310400.

The previous prime is 13320221212937. The next prime is 13320221213051. The reversal of 13320221213040 is 4031212202331.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 13320221213040.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 15119433400 + ... + 15119434280.

It is an arithmetic number, because the mean of its divisors is an integer number (75034103760).

Almost surely, 213320221213040 is an apocalyptic number.

13320221213040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13320221213040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24010913203200).

13320221213040 is an abundant number, since it is smaller than the sum of its proper divisors (34701605193360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13320221213040 is a wasteful number, since it uses less digits than its factorization.

13320221213040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1601 (or 1595 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 13320221213040 its reverse (4031212202331), we get a palindrome (17351433415371).

The spelling of 13320221213040 in words is "thirteen trillion, three hundred twenty billion, two hundred twenty-one million, two hundred thirteen thousand, forty".