133202324000401 has 8 divisors (see below), whose sum is σ = 141040812323304. Its totient is φ = 125364175399680.

The previous prime is 133202324000399. The next prime is 133202324000411. The reversal of 133202324000401 is 104000423202331.

It can be written as a sum of positive squares in 4 ways, for example, as 33145916048001 + 100056407952400 = 5757249^2 + 10002820^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133202324000401 - 2¹ = 133202324000399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133202324000411) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 84123070 + ... + 85691863.

It is an arithmetic number, because the mean of its divisors is an integer number (17630101540413).

Almost surely, 2^{133202324000401} is an apocalyptic number.

It is an amenable number.

133202324000401 is a deficient number, since it is larger than the sum of its proper divisors (7838488322903).

133202324000401 is a wasteful number, since it uses less digits than its factorization.

133202324000401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 169861091.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 133202324000401 its reverse (104000423202331), we get a palindrome (237202747202732).

The spelling of 133202324000401 in words is "one hundred thirty-three trillion, two hundred two billion, three hundred twenty-four million, four hundred one", and thus it is an aban number.