Base | Representation |
---|---|
bin | 11110010010010111010000… |
… | …000010010100010010111111 |
3 | 122110122010000202211110012001 |
4 | 132102113100002110102333 |
5 | 114424400340110103244 |
6 | 1151144431210123131 |
7 | 40025423136131011 |
oct | 3622272002242277 |
9 | 573563022743161 |
10 | 133203311019199 |
11 | 39496230515903 |
12 | 12b3383b4204a7 |
13 | 5943031373cc5 |
14 | 24c7108bc01b1 |
15 | 105edccc8e5d4 |
hex | 7925d00944bf |
133203311019199 has 2 divisors, whose sum is σ = 133203311019200. Its totient is φ = 133203311019198.
The previous prime is 133203311019197. The next prime is 133203311019217. The reversal of 133203311019199 is 991910113302331.
It is a weak prime.
It is an emirp because it is prime and its reverse (991910113302331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133203311019199 - 21 = 133203311019197 is a prime.
It is a super-2 number, since 2×1332033110191992 (a number of 29 digits) contains 22 as substring.
Together with 133203311019197, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133203311019197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66601655509599 + 66601655509600.
It is an arithmetic number, because the mean of its divisors is an integer number (66601655509600).
Almost surely, 2133203311019199 is an apocalyptic number.
133203311019199 is a deficient number, since it is larger than the sum of its proper divisors (1).
133203311019199 is an equidigital number, since it uses as much as digits as its factorization.
133203311019199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 118098, while the sum is 46.
The spelling of 133203311019199 in words is "one hundred thirty-three trillion, two hundred three billion, three hundred eleven million, nineteen thousand, one hundred ninety-nine".
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