Base | Representation |
---|---|
bin | 10011011000100100010… |
… | …111101100110110011000 |
3 | 11201100020212011220202122 |
4 | 103120210113230312120 |
5 | 133311014303221202 |
6 | 2455534011320412 |
7 | 165144304434560 |
oct | 23304427546630 |
9 | 4640225156678 |
10 | 1332050054552 |
11 | 473a12590588 |
12 | 1961b0a50108 |
13 | 987c5110a69 |
14 | 48685d9bda0 |
15 | 249b29ec9a2 |
hex | 136245ecd98 |
1332050054552 has 64 divisors (see below), whose sum is σ = 3006071635200. Its totient is φ = 540571812480.
The previous prime is 1332050054521. The next prime is 1332050054593. The reversal of 1332050054552 is 2554500502331.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1915802 + ... + 2516822.
It is an arithmetic number, because the mean of its divisors is an integer number (46969869300).
Almost surely, 21332050054552 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1332050054552, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1503035817600).
1332050054552 is an abundant number, since it is smaller than the sum of its proper divisors (1674021580648).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1332050054552 is a wasteful number, since it uses less digits than its factorization.
1332050054552 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 603136 (or 603132 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 35.
Adding to 1332050054552 its reverse (2554500502331), we get a palindrome (3886550556883).
The spelling of 1332050054552 in words is "one trillion, three hundred thirty-two billion, fifty million, fifty-four thousand, five hundred fifty-two".
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