Base | Representation |
---|---|
bin | 111110000001110101… |
… | …0010010110110101101 |
3 | 110201211022110200210021 |
4 | 1330003222102312231 |
5 | 4140301040430401 |
6 | 141105502042141 |
7 | 12423645155506 |
oct | 1740352226655 |
9 | 421738420707 |
10 | 133205405101 |
11 | 51545a8445a |
12 | 21996279351 |
13 | c73acb6642 |
14 | 663909dbad |
15 | 36e947d2a1 |
hex | 1f03a92dad |
133205405101 has 2 divisors, whose sum is σ = 133205405102. Its totient is φ = 133205405100.
The previous prime is 133205405089. The next prime is 133205405131. The reversal of 133205405101 is 101504502331.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 129563282601 + 3642122500 = 359949^2 + 60350^2 .
It is an emirp because it is prime and its reverse (101504502331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133205405101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133205405131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66602702550 + 66602702551.
It is an arithmetic number, because the mean of its divisors is an integer number (66602702551).
Almost surely, 2133205405101 is an apocalyptic number.
It is an amenable number.
133205405101 is a deficient number, since it is larger than the sum of its proper divisors (1).
133205405101 is an equidigital number, since it uses as much as digits as its factorization.
133205405101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 133205405101 its reverse (101504502331), we get a palindrome (234709907432).
The spelling of 133205405101 in words is "one hundred thirty-three billion, two hundred five million, four hundred five thousand, one hundred one".
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