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133208919917 is a prime number
BaseRepresentation
bin111110000001111011…
…1101100111101101101
3110201211120002021012122
41330003313230331231
54140302440414132
6141110105242325
712424020065003
oct1740367547555
9421746067178
10133208919917
1151547a65167
12219974933a5
13c73b947408
146639736a73
1536e9924912
hex1f03decf6d

133208919917 has 2 divisors, whose sum is σ = 133208919918. Its totient is φ = 133208919916.

The previous prime is 133208919871. The next prime is 133208919919. The reversal of 133208919917 is 719919802331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100353369796 + 32855550121 = 316786^2 + 181261^2 .

It is a cyclic number.

It is not a de Polignac number, because 133208919917 - 26 = 133208919853 is a prime.

Together with 133208919919, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133208919919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66604459958 + 66604459959.

It is an arithmetic number, because the mean of its divisors is an integer number (66604459959).

Almost surely, 2133208919917 is an apocalyptic number.

It is an amenable number.

133208919917 is a deficient number, since it is larger than the sum of its proper divisors (1).

133208919917 is an equidigital number, since it uses as much as digits as its factorization.

133208919917 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 734832, while the sum is 53.

The spelling of 133208919917 in words is "one hundred thirty-three billion, two hundred eight million, nine hundred nineteen thousand, nine hundred seventeen".