Base | Representation |
---|---|
bin | 111110000001111011… |
… | …1101100111101101101 |
3 | 110201211120002021012122 |
4 | 1330003313230331231 |
5 | 4140302440414132 |
6 | 141110105242325 |
7 | 12424020065003 |
oct | 1740367547555 |
9 | 421746067178 |
10 | 133208919917 |
11 | 51547a65167 |
12 | 219974933a5 |
13 | c73b947408 |
14 | 6639736a73 |
15 | 36e9924912 |
hex | 1f03decf6d |
133208919917 has 2 divisors, whose sum is σ = 133208919918. Its totient is φ = 133208919916.
The previous prime is 133208919871. The next prime is 133208919919. The reversal of 133208919917 is 719919802331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100353369796 + 32855550121 = 316786^2 + 181261^2 .
It is a cyclic number.
It is not a de Polignac number, because 133208919917 - 26 = 133208919853 is a prime.
Together with 133208919919, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133208919919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66604459958 + 66604459959.
It is an arithmetic number, because the mean of its divisors is an integer number (66604459959).
Almost surely, 2133208919917 is an apocalyptic number.
It is an amenable number.
133208919917 is a deficient number, since it is larger than the sum of its proper divisors (1).
133208919917 is an equidigital number, since it uses as much as digits as its factorization.
133208919917 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 734832, while the sum is 53.
The spelling of 133208919917 in words is "one hundred thirty-three billion, two hundred eight million, nine hundred nineteen thousand, nine hundred seventeen".
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