1332101011301 has 4 divisors (see below), whose sum is σ = 1335135410400. Its totient is φ = 1329066612204.

The previous prime is 1332101011231. The next prime is 1332101011309. The reversal of 1332101011301 is 1031101012331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1332101011301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1332101011301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1332101011309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1517198891 + ... + 1517199768.

It is an arithmetic number, because the mean of its divisors is an integer number (333783852600).

Almost surely, 2^{1332101011301} is an apocalyptic number.

It is an amenable number.

1332101011301 is a deficient number, since it is larger than the sum of its proper divisors (3034399099).

1332101011301 is an equidigital number, since it uses as much as digits as its factorization.

1332101011301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3034399098.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1332101011301 its reverse (1031101012331), we get a palindrome (2363202023632).

The spelling of 1332101011301 in words is "one trillion, three hundred thirty-two billion, one hundred one million, eleven thousand, three hundred one".