1332101121121 has 4 divisors (see below), whose sum is σ = 1332351380272. Its totient is φ = 1331850861972.

The previous prime is 1332101121089. The next prime is 1332101121149. The reversal of 1332101121121 is 1211211012331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1332101121121 - 2⁵ = 1332101121089 is a prime.

It is a super-4 number, since 4×1332101121121⁴ (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1332101121181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125121591 + ... + 125132236.

It is an arithmetic number, because the mean of its divisors is an integer number (333087845068).

Almost surely, 2^{1332101121121} is an apocalyptic number.

It is an amenable number.

1332101121121 is a deficient number, since it is larger than the sum of its proper divisors (250259151).

1332101121121 is an equidigital number, since it uses as much as digits as its factorization.

1332101121121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 250259150.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1332101121121 its reverse (1211211012331), we get a palindrome (2543312133452).

The spelling of 1332101121121 in words is "one trillion, three hundred thirty-two billion, one hundred one million, one hundred twenty-one thousand, one hundred twenty-one".