Base | Representation |
---|---|
bin | 1100000111011000101011… |
… | …0111100101101110010111 |
3 | 1202011110220000200121011211 |
4 | 3001312022313211232113 |
5 | 3221222423443210033 |
6 | 44155332122242251 |
7 | 2543261243524525 |
oct | 301661267455627 |
9 | 52143800617154 |
10 | 13321023413143 |
11 | 42764614904a6 |
12 | 15b1853956387 |
13 | 758223208954 |
14 | 340a53333315 |
15 | 18179c86a2cd |
hex | c1d8ade5b97 |
13321023413143 has 2 divisors, whose sum is σ = 13321023413144. Its totient is φ = 13321023413142.
The previous prime is 13321023413141. The next prime is 13321023413153. The reversal of 13321023413143 is 34131432012331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13321023413143 - 21 = 13321023413141 is a prime.
Together with 13321023413141, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13321023413141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660511706571 + 6660511706572.
It is an arithmetic number, because the mean of its divisors is an integer number (6660511706572).
Almost surely, 213321023413143 is an apocalyptic number.
13321023413143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321023413143 is an equidigital number, since it uses as much as digits as its factorization.
13321023413143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 13321023413143 its reverse (34131432012331), we get a palindrome (47452455425474).
The spelling of 13321023413143 in words is "thirteen trillion, three hundred twenty-one billion, twenty-three million, four hundred thirteen thousand, one hundred forty-three".
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