1332110100113 has 8 divisors (see below), whose sum is σ = 1434958378728. Its totient is φ = 1229315860224.

The previous prime is 1332110100071. The next prime is 1332110100133. The reversal of 1332110100113 is 3110010112331.

It can be written as a sum of positive squares in 4 ways, for example, as 41368712449 + 1290741387664 = 203393^2 + 1136108^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1332110100113 - 2¹⁴ = 1332110083729 is a prime.

It is a super-2 number, since 2×1332110100113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1332110100091 and 1332110100100.

It is not an unprimeable number, because it can be changed into a prime (1332110100133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13458470 + ... + 13557087.

It is an arithmetic number, because the mean of its divisors is an integer number (179369797341).

Almost surely, 2^{1332110100113} is an apocalyptic number.

1332110100113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1332110100113 is a deficient number, since it is larger than the sum of its proper divisors (102848278615).

1332110100113 is a wasteful number, since it uses less digits than its factorization.

1332110100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27019363.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1332110100113 its reverse (3110010112331), we get a palindrome (4442120212444).

The spelling of 1332110100113 in words is "one trillion, three hundred thirty-two billion, one hundred ten million, one hundred thousand, one hundred thirteen".