Base | Representation |
---|---|
bin | 10011011000101000100… |
… | …110010111101111011101 |
3 | 11201100102210200210010111 |
4 | 103120220212113233131 |
5 | 133311140434242432 |
6 | 2455545024210021 |
7 | 165146125515313 |
oct | 23305046275735 |
9 | 4640383623114 |
10 | 1332121009117 |
11 | 473a49643818 |
12 | 196210769911 |
13 | 98806a24c02 |
14 | 4869158c0b3 |
15 | 249b8d66347 |
hex | 13628997bdd |
1332121009117 has 2 divisors, whose sum is σ = 1332121009118. Its totient is φ = 1332121009116.
The previous prime is 1332121009097. The next prime is 1332121009123. The reversal of 1332121009117 is 7119001212331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1150189755961 + 181931253156 = 1072469^2 + 426534^2 .
It is a cyclic number.
It is not a de Polignac number, because 1332121009117 - 231 = 1329973525469 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1332121009127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666060504558 + 666060504559.
It is an arithmetic number, because the mean of its divisors is an integer number (666060504559).
Almost surely, 21332121009117 is an apocalyptic number.
It is an amenable number.
1332121009117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332121009117 is an equidigital number, since it uses as much as digits as its factorization.
1332121009117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2268, while the sum is 31.
The spelling of 1332121009117 in words is "one trillion, three hundred thirty-two billion, one hundred twenty-one million, nine thousand, one hundred seventeen".
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