133212203131231 has 4 divisors (see below), whose sum is σ = 152242517864272. Its totient is φ = 114181888398192.

The previous prime is 133212203131229. The next prime is 133212203131253. The reversal of 133212203131231 is 132131302212331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133212203131231 - 2¹ = 133212203131229 is a prime.

It is a super-3 number, since 3×133212203131231³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 133212203131231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133212203131831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9515157366510 + ... + 9515157366523.

It is an arithmetic number, because the mean of its divisors is an integer number (38060629466068).

Almost surely, 2^{133212203131231} is an apocalyptic number.

133212203131231 is a deficient number, since it is larger than the sum of its proper divisors (19030314733041).

133212203131231 is an equidigital number, since it uses as much as digits as its factorization.

133212203131231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19030314733040.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 133212203131231 its reverse (132131302212331), we get a palindrome (265343505343562).

The spelling of 133212203131231 in words is "one hundred thirty-three trillion, two hundred twelve billion, two hundred three million, one hundred thirty-one thousand, two hundred thirty-one".