Base | Representation |
---|---|
bin | 10011011000101001110… |
… | …010110101110100001111 |
3 | 11201100111012102020020202 |
4 | 103120221302311310033 |
5 | 133311211102231442 |
6 | 2455551022004115 |
7 | 165146461065662 |
oct | 23305162656417 |
9 | 4640435366222 |
10 | 1332141055247 |
11 | 473a59995772 |
12 | 19621741663b |
13 | 9880ac23322 |
14 | 486940c96d9 |
15 | 249ba9c5c32 |
hex | 13629cb5d0f |
1332141055247 has 2 divisors, whose sum is σ = 1332141055248. Its totient is φ = 1332141055246.
The previous prime is 1332141055207. The next prime is 1332141055249. The reversal of 1332141055247 is 7425501412331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1332141055247 - 232 = 1327846087951 is a prime.
Together with 1332141055249, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1332141055247.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1332141055249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666070527623 + 666070527624.
It is an arithmetic number, because the mean of its divisors is an integer number (666070527624).
Almost surely, 21332141055247 is an apocalyptic number.
1332141055247 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332141055247 is an equidigital number, since it uses as much as digits as its factorization.
1332141055247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 38.
Adding to 1332141055247 its reverse (7425501412331), we get a palindrome (8757642467578).
The spelling of 1332141055247 in words is "one trillion, three hundred thirty-two billion, one hundred forty-one million, fifty-five thousand, two hundred forty-seven".
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