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133214411124143 = 235791930918441
BaseRepresentation
bin11110010010100001100101…
…101001110110110110101111
3122110200011200100122012120222
4132102201211221312312233
5114430041103221433033
61151153504452001555
740026265202354006
oct3622414551666657
9573604610565528
10133214411124143
113949aa07206a58
1212b35a189002bb
1359440acc4ab3b
1424c787d0abc3d
15106032c504598
hex792865a76daf

133214411124143 has 4 divisors (see below), whose sum is σ = 139006342042608. Its totient is φ = 127422480205680.

The previous prime is 133214411124107. The next prime is 133214411124167. The reversal of 133214411124143 is 341421114412331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133214411124143 - 214 = 133214411107759 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133214411126143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2895965459198 + ... + 2895965459243.

It is an arithmetic number, because the mean of its divisors is an integer number (34751585510652).

Almost surely, 2133214411124143 is an apocalyptic number.

133214411124143 is a deficient number, since it is larger than the sum of its proper divisors (5791930918465).

133214411124143 is an equidigital number, since it uses as much as digits as its factorization.

133214411124143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5791930918464.

The product of its digits is 27648, while the sum is 35.

Adding to 133214411124143 its reverse (341421114412331), we get a palindrome (474635525536474).

The spelling of 133214411124143 in words is "one hundred thirty-three trillion, two hundred fourteen billion, four hundred eleven million, one hundred twenty-four thousand, one hundred forty-three".

Divisors: 1 23 5791930918441 133214411124143