Base | Representation |
---|---|
bin | 1100000111011100011001… |
… | …0001101110011001001111 |
3 | 1202011120110111011120010220 |
4 | 3001313012101232121033 |
5 | 3221231444122321033 |
6 | 44200015045202423 |
7 | 2543325035432040 |
oct | 301670621563117 |
9 | 52146414146126 |
10 | 13322020120143 |
11 | 4276923065199 |
12 | 15b1a91700413 |
13 | 758351861cc7 |
14 | 340b098648c7 |
15 | 18180a0eabb3 |
hex | c1dc646e64f |
13322020120143 has 8 divisors (see below), whose sum is σ = 20300221135488. Its totient is φ = 7612582925784.
The previous prime is 13322020120141. The next prime is 13322020120163. The reversal of 13322020120143 is 34102102022331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13322020120143 - 21 = 13322020120141 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13322020120141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 317190955221 + ... + 317190955262.
It is an arithmetic number, because the mean of its divisors is an integer number (2537527641936).
Almost surely, 213322020120143 is an apocalyptic number.
13322020120143 is a deficient number, since it is larger than the sum of its proper divisors (6978201015345).
13322020120143 is an equidigital number, since it uses as much as digits as its factorization.
13322020120143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 634381910493.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13322020120143 its reverse (34102102022331), we get a palindrome (47424122142474).
The spelling of 13322020120143 in words is "thirteen trillion, three hundred twenty-two billion, twenty million, one hundred twenty thousand, one hundred forty-three".
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