Base | Representation |
---|---|
bin | 11000110100000111… |
… | …11111010000100101 |
3 | 1021101102222121002211 |
4 | 30122003333100211 |
5 | 204240432430140 |
6 | 10041540003421 |
7 | 651064310113 |
oct | 143203772045 |
9 | 37342877084 |
10 | 13322155045 |
11 | 57170112a1 |
12 | 26b9690571 |
13 | 1344058aa4 |
14 | 905468ab3 |
15 | 52e88a2ea |
hex | 31a0ff425 |
13322155045 has 32 divisors (see below), whose sum is σ = 17108582400. Its totient is φ = 9928961856.
The previous prime is 13322155031. The next prime is 13322155061. The reversal of 13322155045 is 54055122331.
13322155045 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13322155045 - 211 = 13322152997 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13322154998 and 13322155016.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4625916 + ... + 4628794.
It is an arithmetic number, because the mean of its divisors is an integer number (534643200).
Almost surely, 213322155045 is an apocalyptic number.
It is an amenable number.
13322155045 is a deficient number, since it is larger than the sum of its proper divisors (3786427355).
13322155045 is a wasteful number, since it uses less digits than its factorization.
13322155045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3697.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 13322155045 its reverse (54055122331), we get a palindrome (67377277376).
The spelling of 13322155045 in words is "thirteen billion, three hundred twenty-two million, one hundred fifty-five thousand, forty-five".
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