Base | Representation |
---|---|
bin | 11110010010101001101100… |
… | …110011011001011111010100 |
3 | 122110201000011100210202122122 |
4 | 132102221230303121133110 |
5 | 114430211422434003104 |
6 | 1151201505030515112 |
7 | 40030024063161161 |
oct | 3622515463313724 |
9 | 573630140722578 |
10 | 133223121000404 |
11 | 394a36767599a6 |
12 | 12b37649805a98 |
13 | 5944b6a57a786 |
14 | 24c8067b61068 |
15 | 106068bec36be |
hex | 792a6ccd97d4 |
133223121000404 has 24 divisors (see below), whose sum is σ = 238830851313600. Its totient is φ = 64985789833920.
The previous prime is 133223121000383. The next prime is 133223121000439. The reversal of 133223121000404 is 404000121322331.
133223121000404 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2909057 + ... + 16580375.
It is an arithmetic number, because the mean of its divisors is an integer number (9951285471400).
Almost surely, 2133223121000404 is an apocalyptic number.
It is an amenable number.
133223121000404 is a deficient number, since it is larger than the sum of its proper divisors (105607730313196).
133223121000404 is a wasteful number, since it uses less digits than its factorization.
133223121000404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13730783 (or 13730781 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 133223121000404 its reverse (404000121322331), we get a palindrome (537223242322735).
The spelling of 133223121000404 in words is "one hundred thirty-three trillion, two hundred twenty-three billion, one hundred twenty-one million, four hundred four", and thus it is an aban number.
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