133230000041 has 4 divisors (see below), whose sum is σ = 133247984784. Its totient is φ = 133212015300.

The previous prime is 133230000023. The next prime is 133230000067. The reversal of 133230000041 is 140000032331.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 140000032331 = 337 ⋅415430363.

It is a cyclic number.

It is not a de Polignac number, because 133230000041 - 2¹⁰ = 133229999017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 133229999974 and 133230000019.

It is not an unprimeable number, because it can be changed into a prime (133230030041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8981255 + ... + 8996076.

It is an arithmetic number, because the mean of its divisors is an integer number (33311996196).

Almost surely, 2^133230000041 is an apocalyptic number.

It is an amenable number.

133230000041 is a deficient number, since it is larger than the sum of its proper divisors (17984743).

133230000041 is an equidigital number, since it uses as much as digits as its factorization.

133230000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17984742.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 133230000041 its reverse (140000032331), we get a palindrome (273230032372).

The spelling of 133230000041 in words is "one hundred thirty-three billion, two hundred thirty million, forty-one", and thus it is an aban number.