Search a number
-
+
1332302435133 = 3444100811711
BaseRepresentation
bin10011011000110011011…
…010011101001100111101
311201100220110002011211120
4103120303122131030331
5133312023410411013
62500015024541153
7165153460563165
oct23306332351475
94640813064746
101332302435133
11474031a9a87a
121962614817b9
13988354a7b97
14486ab6d75a5
15249c9c52123
hex1363369d33d

1332302435133 has 4 divisors (see below), whose sum is σ = 1776403246848. Its totient is φ = 888201623420.

The previous prime is 1332302435129. The next prime is 1332302435203. The reversal of 1332302435133 is 3315342032331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1332302435133 - 22 = 1332302435129 is a prime.

It is a super-2 number, since 2×13323024351332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1332302435094 and 1332302435103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1332302435533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222050405853 + ... + 222050405858.

It is an arithmetic number, because the mean of its divisors is an integer number (444100811712).

Almost surely, 21332302435133 is an apocalyptic number.

It is an amenable number.

1332302435133 is a deficient number, since it is larger than the sum of its proper divisors (444100811715).

1332302435133 is an equidigital number, since it uses as much as digits as its factorization.

1332302435133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 444100811714.

The product of its (nonzero) digits is 58320, while the sum is 33.

Adding to 1332302435133 its reverse (3315342032331), we get a palindrome (4647644467464).

The spelling of 1332302435133 in words is "one trillion, three hundred thirty-two billion, three hundred two million, four hundred thirty-five thousand, one hundred thirty-three".

Divisors: 1 3 444100811711 1332302435133