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13323031002000 = 24325317197331391
BaseRepresentation
bin1100000111100000001010…
…0001111011101110010000
31202011200001221022200100200
43001320002201323232100
53221241031414031000
644200303240015200
72543362061664336
oct301700241735620
952150057280320
1013323031002000
1142772a1740745
1215b2114161500
1375848310c255
14340ba3c05b56
15181868c2b500
hexc1e0287bb90

13323031002000 has 960 divisors, whose sum is σ = 52575432099840. Its totient is φ = 3124334592000.

The previous prime is 13323031001993. The next prime is 13323031002049. The reversal of 13323031002000 is 20013032331.

13323031002000 is a `hidden beast` number, since 1 + 332 + 3 + 0 + 310 + 0 + 20 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 424406305 + ... + 424437695.

It is an arithmetic number, because the mean of its divisors is an integer number (54766075104).

Almost surely, 213323031002000 is an apocalyptic number.

13323031002000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13323031002000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26287716049920).

13323031002000 is an abundant number, since it is smaller than the sum of its proper divisors (39252401097840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13323031002000 is a wasteful number, since it uses less digits than its factorization.

13323031002000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31529 (or 31510 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 18.

Adding to 13323031002000 its reverse (20013032331), we get a palindrome (13343044034331).

The spelling of 13323031002000 in words is "thirteen trillion, three hundred twenty-three billion, thirty-one million, two thousand".