Base | Representation |
---|---|
bin | 1100000111100000011111… |
… | …0001010101100001111110 |
3 | 1202011200022001202200100021 |
4 | 3001320013301111201332 |
5 | 3221241221421112300 |
6 | 44200320100322354 |
7 | 2543364210222361 |
oct | 301700761254176 |
9 | 52150261680307 |
10 | 13323118925950 |
11 | 4277337334269 |
12 | 15b21396a33ba |
13 | 7584983b5262 |
14 | 340bb17720d8 |
15 | 1818717e7d1a |
hex | c1e07c5587e |
13323118925950 has 24 divisors (see below), whose sum is σ = 24785669430360. Its totient is φ = 5328243650400.
The previous prime is 13323118925933. The next prime is 13323118925951. The reversal of 13323118925950 is 5952981132331.
13323118925950 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13323118925951) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 24829896 + ... + 25360795.
It is an arithmetic number, because the mean of its divisors is an integer number (1032736226265).
Almost surely, 213323118925950 is an apocalyptic number.
13323118925950 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13323118925950 is a deficient number, since it is larger than the sum of its proper divisors (11462550504410).
13323118925950 is a wasteful number, since it uses less digits than its factorization.
13323118925950 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50196012 (or 50196007 counting only the distinct ones).
The product of its (nonzero) digits is 1749600, while the sum is 52.
The spelling of 13323118925950 in words is "thirteen trillion, three hundred twenty-three billion, one hundred eighteen million, nine hundred twenty-five thousand, nine hundred fifty".
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