Base | Representation |
---|---|
bin | 111110000010100111… |
… | …1110000000001001111 |
3 | 110201220011111220122101 |
4 | 1330011033300001033 |
5 | 4140324343013403 |
6 | 141112252055531 |
7 | 12424420216045 |
oct | 1740517600117 |
9 | 421804456571 |
10 | 133232001103 |
11 | 51559a9a423 |
12 | 219a31645a7 |
13 | c743669116 |
14 | 663c824395 |
15 | 36eb98371d |
hex | 1f053f004f |
133232001103 has 4 divisors (see below), whose sum is σ = 133232742720. Its totient is φ = 133231259488.
The previous prime is 133232001079. The next prime is 133232001121. The reversal of 133232001103 is 301100232331.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133232001103 is a prime.
It is a super-2 number, since 2×1332320011032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133232001703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87426 + ... + 523552.
It is an arithmetic number, because the mean of its divisors is an integer number (33308185680).
Almost surely, 2133232001103 is an apocalyptic number.
133232001103 is a deficient number, since it is larger than the sum of its proper divisors (741617).
133232001103 is an equidigital number, since it uses as much as digits as its factorization.
133232001103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 741616.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 133232001103 its reverse (301100232331), we get a palindrome (434332233434).
The spelling of 133232001103 in words is "one hundred thirty-three billion, two hundred thirty-two million, one thousand, one hundred three".
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