Base | Representation |
---|---|
bin | 11110010010110010010111… |
… | …000101111000111100100000 |
3 | 122110201220011110022111200111 |
4 | 132102302113011320330200 |
5 | 114430334444112104004 |
6 | 1151210043505501104 |
7 | 40030503403035541 |
oct | 3622622705707440 |
9 | 573656143274614 |
10 | 133232420425504 |
11 | 394a7608a71694 |
12 | 12b39404041794 |
13 | 59459c0086c8a |
14 | 24c86aac3a4c8 |
15 | 1060a335e8a04 |
hex | 792c97178f20 |
133232420425504 has 12 divisors (see below), whose sum is σ = 262301327712774. Its totient is φ = 66616210212736.
The previous prime is 133232420425499. The next prime is 133232420425519. The reversal of 133232420425504 is 405524024232331.
It can be written as a sum of positive squares in only one way, i.e., 125010735872400 + 8221684553104 = 11180820^2 + 2867348^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2081756569117 + ... + 2081756569180.
Almost surely, 2133232420425504 is an apocalyptic number.
It is an amenable number.
133232420425504 is a deficient number, since it is larger than the sum of its proper divisors (129068907287270).
133232420425504 is an equidigital number, since it uses as much as digits as its factorization.
133232420425504 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4163513138307 (or 4163513138299 counting only the distinct ones).
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 133232420425504 its reverse (405524024232331), we get a palindrome (538756444657835).
The spelling of 133232420425504 in words is "one hundred thirty-three trillion, two hundred thirty-two billion, four hundred twenty million, four hundred twenty-five thousand, five hundred four".
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