Base | Representation |
---|---|
bin | 1100000111100001010001… |
… | …1111010110000000001100 |
3 | 1202011200211221021212111001 |
4 | 3001320110133112000030 |
5 | 3221242141033004400 |
6 | 44200353202110044 |
7 | 2543402411044345 |
oct | 301702437260014 |
9 | 52150757255431 |
10 | 13323332313100 |
11 | 4277436830187 |
12 | 15b219904b324 |
13 | 758500678a44 |
14 | 340bd1c3b0cc |
15 | 1818853e8a6a |
hex | c1e147d600c |
13323332313100 has 36 divisors (see below), whose sum is σ = 28916253163224. Its totient is φ = 5328480935680.
The previous prime is 13323332313089. The next prime is 13323332313113. The reversal of 13323332313100 is 131323332331.
It is a super-2 number, since 2×133233323131002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10021042 + ... + 11272441.
It is an arithmetic number, because the mean of its divisors is an integer number (803229254534).
Almost surely, 213323332313100 is an apocalyptic number.
13323332313100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13323332313100 is an abundant number, since it is smaller than the sum of its proper divisors (15592920850124).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13323332313100 is a wasteful number, since it uses less digits than its factorization.
13323332313100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21299754 (or 21299747 counting only the distinct ones).
The product of its (nonzero) digits is 8748, while the sum is 28.
Adding to 13323332313100 its reverse (131323332331), we get a palindrome (13454655645431).
The spelling of 13323332313100 in words is "thirteen trillion, three hundred twenty-three billion, three hundred thirty-two million, three hundred thirteen thousand, one hundred".
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