Base | Representation |
---|---|
bin | 11000110100010101… |
… | …00110110110000011 |
3 | 1021101120020202002022 |
4 | 30122022212312003 |
5 | 204241403440201 |
6 | 10042041112055 |
7 | 651115124333 |
oct | 143212466603 |
9 | 37346222068 |
10 | 13323890051 |
11 | 5717a9688a |
12 | 26ba18862b |
13 | 1344515714 |
14 | 90579b0c3 |
15 | 52eace41b |
hex | 31a2a6d83 |
13323890051 has 2 divisors, whose sum is σ = 13323890052. Its totient is φ = 13323890050.
The previous prime is 13323890009. The next prime is 13323890053. The reversal of 13323890051 is 15009832331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13323890051 - 210 = 13323889027 is a prime.
It is a super-2 number, since 2×133238900512 (a number of 21 digits) contains 22 as substring.
Together with 13323890053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13323889993 and 13323890020.
It is not a weakly prime, because it can be changed into another prime (13323890053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661945025 + 6661945026.
It is an arithmetic number, because the mean of its divisors is an integer number (6661945026).
Almost surely, 213323890051 is an apocalyptic number.
13323890051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13323890051 is an equidigital number, since it uses as much as digits as its factorization.
13323890051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 35.
The spelling of 13323890051 in words is "thirteen billion, three hundred twenty-three million, eight hundred ninety thousand, fifty-one".
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