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13323896243519 is a prime number
BaseRepresentation
bin1100000111100011011000…
…0110100100010100111111
31202011202022020102111120212
43001320312012210110333
53221244314414243034
644200525145103035
72543422366265351
oct301706606442477
952152266374525
1013323896243519
1142776a6092484
1215b2315a87a7b
13758590455a94
14340c46ab50d1
151818b9b8e2ce
hexc1e361a453f

13323896243519 has 2 divisors, whose sum is σ = 13323896243520. Its totient is φ = 13323896243518.

The previous prime is 13323896243507. The next prime is 13323896243531. The reversal of 13323896243519 is 91534269832331.

13323896243519 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13323896243507) and next prime (13323896243531).

It is a cyclic number.

It is not a de Polignac number, because 13323896243519 - 28 = 13323896243263 is a prime.

It is a super-2 number, since 2×133238962435192 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13323896243419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661948121759 + 6661948121760.

It is an arithmetic number, because the mean of its divisors is an integer number (6661948121760).

Almost surely, 213323896243519 is an apocalyptic number.

13323896243519 is a deficient number, since it is larger than the sum of its proper divisors (1).

13323896243519 is an equidigital number, since it uses as much as digits as its factorization.

13323896243519 is an evil number, because the sum of its binary digits is even.

The product of its digits is 25194240, while the sum is 59.

The spelling of 13323896243519 in words is "thirteen trillion, three hundred twenty-three billion, eight hundred ninety-six million, two hundred forty-three thousand, five hundred nineteen".