Base | Representation |
---|---|
bin | 11000110100010110… |
… | …00010011110101001 |
3 | 1021101120110111100112 |
4 | 30122023002132221 |
5 | 204241421100431 |
6 | 10042043344105 |
7 | 651116105333 |
oct | 143213023651 |
9 | 37346414315 |
10 | 13324003241 |
11 | 571806392a |
12 | 26ba222035 |
13 | 13445550b3 |
14 | 9057ca453 |
15 | 52eb02c2b |
hex | 31a2c27a9 |
13324003241 has 2 divisors, whose sum is σ = 13324003242. Its totient is φ = 13324003240.
The previous prime is 13324003219. The next prime is 13324003243. The reversal of 13324003241 is 14230042331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6876555625 + 6447447616 = 82925^2 + 80296^2 .
It is a cyclic number.
It is not a de Polignac number, because 13324003241 - 214 = 13323986857 is a prime.
Together with 13324003243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13324003243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662001620 + 6662001621.
It is an arithmetic number, because the mean of its divisors is an integer number (6662001621).
Almost surely, 213324003241 is an apocalyptic number.
It is an amenable number.
13324003241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13324003241 is an equidigital number, since it uses as much as digits as its factorization.
13324003241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 13324003241 its reverse (14230042331), we get a palindrome (27554045572).
The spelling of 13324003241 in words is "thirteen billion, three hundred twenty-four million, three thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •