Base | Representation |
---|---|
bin | 11000110100010111… |
… | …00110111001110001 |
3 | 1021101120202002000011 |
4 | 30122023212321301 |
5 | 204241440334213 |
6 | 10042050454521 |
7 | 651120266314 |
oct | 143213467161 |
9 | 37346662004 |
10 | 13324152433 |
11 | 5718155a29 |
12 | 26ba294441 |
13 | 13445a7c87 |
14 | 90582897b |
15 | 52eb3203d |
hex | 31a2e6e71 |
13324152433 has 2 divisors, whose sum is σ = 13324152434. Its totient is φ = 13324152432.
The previous prime is 13324152427. The next prime is 13324152451. The reversal of 13324152433 is 33425142331.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12962277904 + 361874529 = 113852^2 + 19023^2 .
It is a cyclic number.
It is not a de Polignac number, because 13324152433 - 29 = 13324151921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13324152395 and 13324152404.
It is not a weakly prime, because it can be changed into another prime (13324152463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662076216 + 6662076217.
It is an arithmetic number, because the mean of its divisors is an integer number (6662076217).
Almost surely, 213324152433 is an apocalyptic number.
It is an amenable number.
13324152433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13324152433 is an equidigital number, since it uses as much as digits as its factorization.
13324152433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25920, while the sum is 31.
Adding to 13324152433 its reverse (33425142331), we get a palindrome (46749294764).
The spelling of 13324152433 in words is "thirteen billion, three hundred twenty-four million, one hundred fifty-two thousand, four hundred thirty-three".
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