Base | Representation |
---|---|
bin | 11000110100010111… |
… | …00110111010000011 |
3 | 1021101120202002000211 |
4 | 30122023212322003 |
5 | 204241440334301 |
6 | 10042050454551 |
7 | 651120266341 |
oct | 143213467203 |
9 | 37346662024 |
10 | 13324152451 |
11 | 5718155a45 |
12 | 26ba294457 |
13 | 13445a7c9c |
14 | 905828991 |
15 | 52eb32051 |
hex | 31a2e6e83 |
13324152451 has 2 divisors, whose sum is σ = 13324152452. Its totient is φ = 13324152450.
The previous prime is 13324152433. The next prime is 13324152463. The reversal of 13324152451 is 15425142331.
13324152451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13324152451 - 211 = 13324150403 is a prime.
It is not a weakly prime, because it can be changed into another prime (13324155451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662076225 + 6662076226.
It is an arithmetic number, because the mean of its divisors is an integer number (6662076226).
Almost surely, 213324152451 is an apocalyptic number.
13324152451 is a deficient number, since it is larger than the sum of its proper divisors (1).
13324152451 is an equidigital number, since it uses as much as digits as its factorization.
13324152451 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 14400, while the sum is 31.
Adding to 13324152451 its reverse (15425142331), we get a palindrome (28749294782).
The spelling of 13324152451 in words is "thirteen billion, three hundred twenty-four million, one hundred fifty-two thousand, four hundred fifty-one".
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