Base | Representation |
---|---|
bin | 111110000010111011… |
… | …0000000111110010111 |
3 | 110201220212101112110221 |
4 | 1330011312000332113 |
5 | 4140334430011043 |
6 | 141113251055211 |
7 | 12424601404522 |
oct | 1740566007627 |
9 | 421825345427 |
10 | 133242032023 |
11 | 51564720841 |
12 | 219a65a1507 |
13 | c74576ba89 |
14 | 663dcb5bb9 |
15 | 36ec7b58ed |
hex | 1f05d80f97 |
133242032023 has 4 divisors (see below), whose sum is σ = 133267675480. Its totient is φ = 133216388568.
The previous prime is 133242031933. The next prime is 133242032071. The reversal of 133242032023 is 320230242331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 320230242331 = 47207 ⋅6783533.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133242032023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133242032083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12813933 + ... + 12824326.
It is an arithmetic number, because the mean of its divisors is an integer number (33316918870).
Almost surely, 2133242032023 is an apocalyptic number.
133242032023 is a deficient number, since it is larger than the sum of its proper divisors (25643457).
133242032023 is an equidigital number, since it uses as much as digits as its factorization.
133242032023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25643456.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 133242032023 its reverse (320230242331), we get a palindrome (453472274354).
The spelling of 133242032023 in words is "one hundred thirty-three billion, two hundred forty-two million, thirty-two thousand, twenty-three".
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