13324566656047 has 4 divisors (see below), whose sum is σ = 14108364694656. Its totient is φ = 12540768617440.

The previous prime is 13324566656041. The next prime is 13324566656101. The reversal of 13324566656047 is 74065666542331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13324566656047 - 2³ = 13324566656039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13324566655982 and 13324566656000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13324566656041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 391899019279 + ... + 391899019312.

It is an arithmetic number, because the mean of its divisors is an integer number (3527091173664).

Almost surely, 2^{13324566656047} is an apocalyptic number.

13324566656047 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

13324566656047 is a deficient number, since it is larger than the sum of its proper divisors (783798038609).

13324566656047 is an equidigital number, since it uses as much as digits as its factorization.

13324566656047 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 783798038608.

The product of its (nonzero) digits is 65318400, while the sum is 58.

The spelling of 13324566656047 in words is "thirteen trillion, three hundred twenty-four billion, five hundred sixty-six million, six hundred fifty-six thousand, forty-seven".