Base | Representation |
---|---|
bin | 11000110100011011… |
… | …01000010100110111 |
3 | 1021101121202000012011 |
4 | 30122031220110313 |
5 | 204242104320201 |
6 | 10042110105051 |
7 | 651124634665 |
oct | 143215502467 |
9 | 37347660164 |
10 | 13324682551 |
11 | 5718488244 |
12 | 26ba4ab187 |
13 | 134473235b |
14 | 905925c35 |
15 | 52ebd9151 |
hex | 31a368537 |
13324682551 has 4 divisors (see below), whose sum is σ = 13325197312. Its totient is φ = 13324167792.
The previous prime is 13324682513. The next prime is 13324682557. The reversal of 13324682551 is 15528642331.
13324682551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13324682551 - 29 = 13324682039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13324682557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216375 + ... + 271048.
It is an arithmetic number, because the mean of its divisors is an integer number (3331299328).
Almost surely, 213324682551 is an apocalyptic number.
13324682551 is a deficient number, since it is larger than the sum of its proper divisors (514761).
13324682551 is an equidigital number, since it uses as much as digits as its factorization.
13324682551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 514760.
The product of its digits is 172800, while the sum is 40.
The spelling of 13324682551 in words is "thirteen billion, three hundred twenty-four million, six hundred eighty-two thousand, five hundred fifty-one".
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