Base | Representation |
---|---|
bin | 11000110100100000… |
… | …10111110000100011 |
3 | 1021101200002111212221 |
4 | 30122100113300203 |
5 | 204242300313443 |
6 | 10042133331511 |
7 | 651134016646 |
oct | 143220276043 |
9 | 37350074787 |
10 | 13325401123 |
11 | 5718929101 |
12 | 26ba796b97 |
13 | 1344924448 |
14 | 905a71a5d |
15 | 52eccbeed |
hex | 31a417c23 |
13325401123 has 2 divisors, whose sum is σ = 13325401124. Its totient is φ = 13325401122.
The previous prime is 13325401099. The next prime is 13325401127. The reversal of 13325401123 is 32110452331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13325401123 is a prime.
It is a super-2 number, since 2×133254011232 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13325401127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662700561 + 6662700562.
It is an arithmetic number, because the mean of its divisors is an integer number (6662700562).
Almost surely, 213325401123 is an apocalyptic number.
13325401123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13325401123 is an equidigital number, since it uses as much as digits as its factorization.
13325401123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 13325401123 its reverse (32110452331), we get a palindrome (45435853454).
The spelling of 13325401123 in words is "thirteen billion, three hundred twenty-five million, four hundred one thousand, one hundred twenty-three".
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