Base | Representation |
---|---|
bin | 1100000111101101001111… |
… | …0001001011000100001110 |
3 | 1202012000010120211011100021 |
4 | 3001323103301023010032 |
5 | 3221320224101411100 |
6 | 44202043440452354 |
7 | 2543545056116326 |
oct | 301732361130416 |
9 | 52160116734307 |
10 | 13326541435150 |
11 | 4278833244069 |
12 | 15b293391a0ba |
13 | 7588c248c628 |
14 | 34101811c286 |
15 | 1819c1ee9a1a |
hex | c1ed3c4b10e |
13326541435150 has 36 divisors (see below), whose sum is σ = 24879177737856. Its totient is φ = 5310944938800.
The previous prime is 13326541435079. The next prime is 13326541435157. The reversal of 13326541435150 is 5153414562331.
It is a junction number, because it is equal to n+sod(n) for n = 13326541435097 and 13326541435106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13326541435157) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 1857459 + ... + 5486641.
It is an arithmetic number, because the mean of its divisors is an integer number (691088270496).
Almost surely, 213326541435150 is an apocalyptic number.
13326541435150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13326541435150 is a deficient number, since it is larger than the sum of its proper divisors (11552636302706).
13326541435150 is an equidigital number, since it uses as much as digits as its factorization.
13326541435150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3629737 (or 3629461 counting only the distinct ones).
The product of its (nonzero) digits is 648000, while the sum is 43.
Adding to 13326541435150 its reverse (5153414562331), we get a palindrome (18479955997481).
The spelling of 13326541435150 in words is "thirteen trillion, three hundred twenty-six billion, five hundred forty-one million, four hundred thirty-five thousand, one hundred fifty".
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