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13330103412 = 2231110841951
BaseRepresentation
bin11000110101000100…
…10011110001110100
31021101222221102012210
430122202103301310
5204300001302122
610042422213420
7651222003153
oct143242236164
937358842183
1013330103412
11572054aa9a
122700284270
1313458ac872
1490653759a
1553040a40c
hex31a893c74

13330103412 has 12 divisors (see below), whose sum is σ = 31103574656. Its totient is φ = 4443367800.

The previous prime is 13330103401. The next prime is 13330103417. The reversal of 13330103412 is 21430103331.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×133301034122 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13330103417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 555420964 + ... + 555420987.

Almost surely, 213330103412 is an apocalyptic number.

13330103412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13330103412 is an abundant number, since it is smaller than the sum of its proper divisors (17773471244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13330103412 is a wasteful number, since it uses less digits than its factorization.

13330103412 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1110841958 (or 1110841956 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 13330103412 its reverse (21430103331), we get a palindrome (34760206743).

The spelling of 13330103412 in words is "thirteen billion, three hundred thirty million, one hundred three thousand, four hundred twelve".

Divisors: 1 2 3 4 6 12 1110841951 2221683902 3332525853 4443367804 6665051706 13330103412