13331034004031 has 2 divisors, whose sum is σ = 13331034004032. Its totient is φ = 13331034004030.

The previous prime is 13331034004019. The next prime is 13331034004033. The reversal of 13331034004031 is 13040043013331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13331034004031 - 2⁴² = 8932987492927 is a prime.

It is a super-2 number, since 2×13331034004031² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13331034004033, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13331034004033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665517002015 + 6665517002016.

It is an arithmetic number, because the mean of its divisors is an integer number (6665517002016).

Almost surely, 2^{13331034004031} is an apocalyptic number.

13331034004031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13331034004031 is an equidigital number, since it uses as much as digits as its factorization.

13331034004031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 26.

Adding to 13331034004031 its reverse (13040043013331), we get a palindrome (26371077017362).

The spelling of 13331034004031 in words is "thirteen trillion, three hundred thirty-one billion, thirty-four million, four thousand, thirty-one".