13331131000223 has 4 divisors (see below), whose sum is σ = 13332385469400. Its totient is φ = 13329876531048.

The previous prime is 13331131000193. The next prime is 13331131000237. The reversal of 13331131000223 is 32200013113331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13331131000223 - 2¹⁴ = 13331130983839 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13331131000423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 627218648 + ... + 627239901.

It is an arithmetic number, because the mean of its divisors is an integer number (3333096367350).

Almost surely, 2^{13331131000223} is an apocalyptic number.

13331131000223 is a deficient number, since it is larger than the sum of its proper divisors (1254469177).

13331131000223 is a wasteful number, since it uses less digits than its factorization.

13331131000223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1254469176.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 13331131000223 its reverse (32200013113331), we get a palindrome (45531144113554).

The spelling of 13331131000223 in words is "thirteen trillion, three hundred thirty-one billion, one hundred thirty-one million, two hundred twenty-three", and thus it is an aban number.