Search a number
-
+
133311322103 = 153533868291
BaseRepresentation
bin111110000100111111…
…0010101011111110111
3110202002200202211121012
41330021332111133313
54141010144301403
6141124204142435
712426402353441
oct1741176253767
9422080684535
10133311322103
115159a847473
1221a05837a1b
13c756c1c41b
146649191491
153703900ed8
hex1f09f957f7

133311322103 has 4 divisors (see below), whose sum is σ = 133312343928. Its totient is φ = 133310300280.

The previous prime is 133311322091. The next prime is 133311322213. The reversal of 133311322103 is 301223113331.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 133311322103 - 214 = 133311305719 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133311328103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 280613 + ... + 587678.

It is an arithmetic number, because the mean of its divisors is an integer number (33328085982).

Almost surely, 2133311322103 is an apocalyptic number.

133311322103 is a deficient number, since it is larger than the sum of its proper divisors (1021825).

133311322103 is an equidigital number, since it uses as much as digits as its factorization.

133311322103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1021824.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 133311322103 its reverse (301223113331), we get a palindrome (434534435434).

The spelling of 133311322103 in words is "one hundred thirty-three billion, three hundred eleven million, three hundred twenty-two thousand, one hundred three".

Divisors: 1 153533 868291 133311322103