Base | Representation |
---|---|
bin | 11000110101001101… |
… | …00000010101011111 |
3 | 1021102002000022010221 |
4 | 30122212200111133 |
5 | 204300242002143 |
6 | 10042501542211 |
7 | 651234234166 |
oct | 143246402537 |
9 | 37362008127 |
10 | 13331203423 |
11 | 572113149a |
12 | 2700714967 |
13 | 1345ba6465 |
14 | 9067423dd |
15 | 5305762ed |
hex | 31a9a055f |
13331203423 has 8 divisors (see below), whose sum is σ = 13673023056. Its totient is φ = 12990177600.
The previous prime is 13331203421. The next prime is 13331203427. The reversal of 13331203423 is 32430213331.
13331203423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13331203423 - 21 = 13331203421 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13331203421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 164361 + ... + 231682.
It is an arithmetic number, because the mean of its divisors is an integer number (1709127882).
Almost surely, 213331203423 is an apocalyptic number.
13331203423 is a deficient number, since it is larger than the sum of its proper divisors (341819633).
13331203423 is an equidigital number, since it uses as much as digits as its factorization.
13331203423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 396905.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 13331203423 its reverse (32430213331), we get a palindrome (45761416754).
The spelling of 13331203423 in words is "thirteen billion, three hundred thirty-one million, two hundred three thousand, four hundred twenty-three".
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